What’s Google onsite hiring rule?
Maybe this is already discussed, but I still don’t know what’s the hiring rule? I can assume two ways: 1. Calculate average. Say 4 round coding, no hire=1, weak hire=2, hire=3, strong hire =4, then calculate average where > 2.5 go to HC 2. Heuristic way: if there’s one no-hire, directly rej; if there are two strong hire, then directly HC I want to know this so that I can have estimate of expectation for each round. For example we can’t have any no-hire in order to pass HC? Another related question: what performance leads to no hire or weak hire? There are many tricky cases: say: A. walking through the logic but not finish coding, weak hire? B. only give brute force solution, not optimal one, hire? C. Give optimal solution for most but fail the follow-up or part-2? Hire or weak hire? Thanks!
Not on a HC but I believe we air on the side of caution by rejecting even good / “just above the bar” candidates in favor of risking it with a candidate that ends up being a bad employee. Therefore, that makes me assume that 1 NH means you’re out.
I don’t think it’s that clear cut since some people have bombed 1 round not two, and still got offers. So even though 1 bad round can disqualify you, the other rounds can also make up for it.
Agree with Amazon. That’s why multiple rounds. Otherwise it would be like startup where candidates need to clear one by one round